zkfcfbzr , 1 month ago solutionarcsin(y) = arccos(x) implies y = sin(arccos(x)) sin(arccos(x)) can be shown to equal ±sqrt(1-x²) with a simple triangle diagram and the pythagorean theorem, so we have y = ±sqrt(1-x²). This can be easily re-arranged to give x² + y² = 1.
arcsin(y) = arccos(x) implies y = sin(arccos(x))
sin(arccos(x)) can be shown to equal ±sqrt(1-x²) with a simple triangle diagram and the pythagorean theorem, so we have y = ±sqrt(1-x²). This can be easily re-arranged to give x² + y² = 1.